Answer by Jérôme Richard for Poor memcpy performance
Saturating RAM is not as simple as is seems.First of all, at first glance here is the apparent throughput we can compute from the provided numbers:Fill: 1 / 0.4263950000 = 2.34 GB/s (1 GB is...
View ArticlePoor memcpy performance
I am trying to optimize some code for speed and its spending a lot of time doing memcpys. I decided to write a simple test program to measure memcpy on its own to see how fast my memory transfers are...
View Article
More Pages to Explore .....
